Solution 18.3a

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(New page: <math>v=\frac{dh}{dt}=\frac{3t}{25}-\frac{3{{t}^{2}}}{250}</math> When <math>t=\text{1}0</math> <math>v=\frac{3\times 10}{25}-\frac{3\times {{10}^{2}}}{250}=1 \textrm{.}2-1 \textrm{.}2...)
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Revision as of 17:30, 6 October 2010

\displaystyle v=\frac{dh}{dt}=\frac{3t}{25}-\frac{3{{t}^{2}}}{250}

When \displaystyle t=\text{1}0

\displaystyle v=\frac{3\times 10}{25}-\frac{3\times {{10}^{2}}}{250}=1 \textrm{.}2-1 \textrm{.}2=0

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