Solution 18.1a
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(New page: <math>v=\frac{ds}{dt}={{t}^{2}}-\frac{{{t}^{3}}}{20}</math>)
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Revision as of 15:24, 4 October 2010
\displaystyle v=\frac{ds}{dt}={{t}^{2}}-\frac{{{t}^{3}}}{20}