Solution 17.9a
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(New page: Gain in kinetic energy = Loss in potential energy. <math>\begin{align} & 40\times 9 \textrm{.}8\times 12=\frac{1}{2}\times 40\times {{v}^{2}} \\ & v=15 \textrm{.}3\text{ m}{{\text{s}}^{\...)
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Gain in kinetic energy = Loss in potential energy.
\displaystyle \begin{align} & 40\times 9 \textrm{.}8\times 12=\frac{1}{2}\times 40\times {{v}^{2}} \\ & v=15 \textrm{.}3\text{ m}{{\text{s}}^{\text{-1}}} \end{align}
