Solution 16.10b
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(New page: From part a) <math>(5m+2\lambda m-3m-3\lambda m)\mathbf{i}+(mV-\lambda mV+2m+2\lambda m)\mathbf{j}=0\mathbf{i}+0\mathbf{j}</math> Consider the <math>\mathbf{j}</math> component. That is...)
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Revision as of 16:29, 1 October 2010
From part a)
\displaystyle (5m+2\lambda m-3m-3\lambda m)\mathbf{i}+(mV-\lambda mV+2m+2\lambda m)\mathbf{j}=0\mathbf{i}+0\mathbf{j}
Consider the \displaystyle \mathbf{j} component. That is the \displaystyle \mathbf{j} component on the left hand side must be the same as the \displaystyle \mathbf{j} component on the right hand side, that is zero.
\displaystyle \begin{align} & mV-\lambda mV+2m+2\lambda m=0 \\ & V-2V+2+4=0 \\ & -V+6=0 \\ & V=6 \\ \end{align}
Note that \displaystyle V is a dimensionless number.
