Solution 17.2
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(New page: <math>KE=\frac{1}{2}\times 0\textrm{.}25\times {{9}^{2}}=10\textrm{.}125\text{ J}</math>)
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\displaystyle KE=\frac{1}{2}\times 0\textrm{.}25\times {{9}^{2}}=10\textrm{.}125\text{ J}
