Answer 16.7
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(New page: a) <math> 4\textrm{.}72 \text{ m}{{\text{s}}^{-1}} </math> b) <math>58\textrm{.}0{}^\circ</math>)
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a) \displaystyle 4\textrm{.}72 \text{ m}{{\text{s}}^{-1}}
b) \displaystyle 58\textrm{.}0{}^\circ
