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Solution 16.3

From Mechanics

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Ian (Talk | contribs)
(New page: Using <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math> <math>\begin{align} & 3\times 4+5\times (-2)=3\times 0+5v \\ & 12-10=5v \\ & v=\frac{2}{5...)
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Using

mAvA+mBvB=mAuA+mBuB

34+5(−2)=30+5v12−10=5vv=52=0.4 ms-1

Continues to move in same direction at a speed 0.4 ms-1.

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