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Solution 16.1

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Ian (Talk | contribs)
(New page: Using <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math> and <math>{{u}_{A}}={{u}_{B}}</math> <math>\begin{align} & 1000\times 20+4000\times 10=(1...)
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Using

mAvA+mBvB=mAuA+mBuB

and

uA=uB

100020+400010=(1000+4000)vv=500060000=12 ms-1