Solution 15.8c
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(New page: <math>\begin{align} & \tan \alpha =\frac{1\textrm{.}92}{15} \\ & \\ & \alpha =7\textrm{.}29{}^\circ \\ \end{align}</math>)
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Revision as of 13:37, 17 September 2010
\displaystyle \begin{align} & \tan \alpha =\frac{1\textrm{.}92}{15} \\ & \\ & \alpha =7\textrm{.}29{}^\circ \\ \end{align}
