Solution 15.7b
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(New page: First find the angle, <math>\alpha </math>, between the impulse and the initial velocity. <math>\begin{align} & \tan \alpha =\frac{12}{24} \\ &\\ & \alpha =26\textrm{.}6{}^\circ \e...)
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Revision as of 11:02, 17 September 2010
First find the angle, \displaystyle \alpha , between the impulse and the initial velocity.
\displaystyle \begin{align} & \tan \alpha =\frac{12}{24} \\ &\\ & \alpha =26\textrm{.}6{}^\circ \end{align}
Then subtract this from \displaystyle {{90}^{\circ }} to get the angle between the initial velocity and the wall.
\displaystyle \text{Angle =}90-26\textrm{.}6={{63\textrm{.}4}^{\circ }}
