Solution 15.5b

From Mechanics

(Difference between revisions)
Jump to: navigation, search
(New page: <math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math> <math>\begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...)
Current revision (18:32, 15 September 2010) (edit) (undo)
 
Line 1: Line 1:
-
<math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math>
+
<math>I=\text{ }0\textrm{.}\text{64} \ \text{Ns}\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math>
<math>\begin{align}
<math>\begin{align}

Current revision

\displaystyle I=\text{ }0\textrm{.}\text{64} \ \text{Ns}\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}

\displaystyle \begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\times 0\textrm{.}2 \\ & F=3\textrm{.}2\text{ N} \end{align}