Solution 15.5b
From Mechanics
(Difference between revisions)
(New page: <math>I=\text{ }0\textrm{.}\text{64}\ \text{kg}\,\text{m}{{\text{s}}^{-1}},\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math> <math>\begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\tim...) |
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- | <math>I=\text{ }0\textrm{.}\text{64}\ \text{ | + | <math>I=\text{ }0\textrm{.}\text{64} \ \text{Ns}\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}</math> |
<math>\begin{align} | <math>\begin{align} |
Current revision
\displaystyle I=\text{ }0\textrm{.}\text{64} \ \text{Ns}\quad t=\text{ }0\textrm{.}\text{2}\ \text{s}
\displaystyle \begin{align} & \\ & I=Ft \\ & 0\textrm{.}64=F\times 0\textrm{.}2 \\ & F=3\textrm{.}2\text{ N} \end{align}