Solution 15.4a

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(New page: <math>\begin{align} & u=0,\quad a=\text{9}\textrm{.}\text{8},\quad s=\text{2} \\ & {{v}^{2}}={{u}^{2}}+2as \\ & {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 2 \\ & v=6\textrm{.}26\tex...)
Current revision (18:32, 14 September 2010) (edit) (undo)
 
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<math>\begin{align}
<math>\begin{align}
-
& u=0,\quad a=\text{9}\textrm{.}\text{8},\quad s=\text{2} \\
+
& u=0\ \text{ m}{{\text{s}}^{-1}},\quad a=\text{9}\textrm{.}\text{8}\ \text{ m}{{\text{s}}^{-2}},\quad s=\text{2 m} \\
& {{v}^{2}}={{u}^{2}}+2as \\
& {{v}^{2}}={{u}^{2}}+2as \\
& {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 2 \\
& {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 2 \\
& v=6\textrm{.}26\text{ m}{{\text{s}}^{\text{-1}}} \\
& v=6\textrm{.}26\text{ m}{{\text{s}}^{\text{-1}}} \\
\end{align}</math>
\end{align}</math>

Current revision

\displaystyle \begin{align} & u=0\ \text{ m}{{\text{s}}^{-1}},\quad a=\text{9}\textrm{.}\text{8}\ \text{ m}{{\text{s}}^{-2}},\quad s=\text{2 m} \\ & {{v}^{2}}={{u}^{2}}+2as \\ & {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 2 \\ & v=6\textrm{.}26\text{ m}{{\text{s}}^{\text{-1}}} \\ \end{align}