Solution 15.4c
From Mechanics
(Difference between revisions)
(New page: <math>\begin{align} & m=\text{ }0\textrm{.}0\text{8},\quad u=\text{ 6}\textrm{.}\text{26},\quad v=\text{ }-\text{5}\textrm{.}\text{24} \\ & \\ & I=mv-mu \\ & =0\textrm{.}08\times (-5\t...) |
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<math>\begin{align} | <math>\begin{align} | ||
| - | & m=\text{ }0\textrm{.}0\text{8},\quad u=\text{ 6}\textrm{.}\text{26},\quad v=\text{ }-\text{5}\textrm{.}\text{24} \\ | + | & m=\text{ }0\textrm{.}0\text{8 kg},\quad u=\text{ 6}\textrm{.}\text{26}\text{ m}{{\text{s}}^{-1}} ,\quad v=\text{ }-\text{5}\textrm{.}\text{24}\text{ m}{{\text{s}}^{-1}} \\ |
& \\ | & \\ | ||
& I=mv-mu \\ | & I=mv-mu \\ | ||
Current revision
\displaystyle \begin{align} & m=\text{ }0\textrm{.}0\text{8 kg},\quad u=\text{ 6}\textrm{.}\text{26}\text{ m}{{\text{s}}^{-1}} ,\quad v=\text{ }-\text{5}\textrm{.}\text{24}\text{ m}{{\text{s}}^{-1}} \\ & \\ & I=mv-mu \\ & =0\textrm{.}08\times (-5\textrm{.}24)-0\textrm{.}08\times 6\textrm{.}26 \\ & =-0\textrm{.}92\text{ Ns} \\ \\ \end{align}
\displaystyle \text{Magnitude of the Impulse }=\text{ }0\textrm{.}\text{92}\ \text{ Ns}
