Answer 14.7
From Mechanics
(Difference between revisions)
(New page: a) <math>\text{ }\frac{10g}{\tan \theta }</math> b) 39.8<math>{}^\circ </math>) |
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| - | a) <math>\text{ }\frac{ | + | a) <math>\text{ }\frac{98}{\tan \theta }\text{ N }</math> |
b) 39.8<math>{}^\circ </math> | b) 39.8<math>{}^\circ </math> | ||
Current revision
a) \displaystyle \text{ }\frac{98}{\tan \theta }\text{ N }
b) 39.8\displaystyle {}^\circ
