Solution 14.4a

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(New page: Taking moments about the left hand support: <math>\begin{align} & 3\times {{R}_{2}}=18\times 9\textrm{.}8\times 2 \\ & {{R}_{2}}=\frac{18\times 9\textrm{.}8\times 2}{3}=117\textrm{.}6\t...)
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Taking moments about the left hand support:


\displaystyle \begin{align} & 3\times {{R}_{2}}=18\times 9\textrm{.}8\times 2 \\ & {{R}_{2}}=\frac{18\times 9\textrm{.}8\times 2}{3}=117\textrm{.}6\text{ N} \\ \end{align}

Taking moments about the right hand support:


\displaystyle \begin{align} & 3\times {{R}_{1}}=18\times 9\textrm{.}8\times 1 \\ & {{R}_{1}}=\frac{18\times 9\textrm{.}8\times 1}{3}=58\textrm{.}8\text{ N} \\ \end{align}

Or:

\displaystyle \begin{align} & {{R}_{1}}+117\textrm{.}6=18\times 9\textrm{.}8 \\ & {{R}_{1}}=18\times 9\textrm{.}8-117.6=58\textrm{.}8\text{ N} \\ \end{align}