Solution 14.1b
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(New page: In this case <math>{{R}_{B}}=0</math>. Taking moments about A: <math>\begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\ti...)
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In this case
\displaystyle {{R}_{B}}=0. Taking moments about A:
\displaystyle \begin{align} & 0\textrm{.}5\times 20\times 9\textrm{.}8=1\times m\times 9\textrm{.}8 \\ & m=\frac{0\textrm{.}5\times 20\times 9\textrm{.}8}{1\times 9\textrm{.}8}=10\text{ kg} \\ \end{align}
