Answer 14.1

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Current revision (17:49, 31 August 2010) (edit) (undo)
 
Line 1: Line 1:
-
a) <math>65\frac{1}{3}\text{ N}\text{, 130}\frac{\text{2}}{\text{3}}\text{ N}</math>
+
a) <math>65 \textrm{.}3 \text{ N}= 65\frac{1}{3}\text{ N}\text{,} \ \ 130 \textrm{.}7 \text{ N}= 130 \frac{\text{2}}{\text{3}}\text{ N}</math>
b) 10 kg
b) 10 kg

Current revision

a) \displaystyle 65 \textrm{.}3 \text{ N}= 65\frac{1}{3}\text{ N}\text{,} \ \ 130 \textrm{.}7 \text{ N}= 130 \frac{\text{2}}{\text{3}}\text{ N}


b) 10 kg