Solution 10.7
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(New page: Image:10.7.gif We have drawn all the forces acting on the block in the figure. The acceleration is represented by the vector <math>a</math>. Applying Newton´s Second Law <math>F=ma<...)
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Revision as of 16:55, 14 June 2010
We have drawn all the forces acting on the block in the figure. The acceleration is represented by the vector \displaystyle a.
Applying Newton´s Second Law \displaystyle F=ma horisontally,
\displaystyle \begin{align} & \to :\ 40\cos {{30}^{\circ }}-F=ma \\ \end{align} ration is represented by the vector \displaystyle a.
