Solution 10.2
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(New page: We first obtain the acceleration <math>a</math>. Using the kinematic equation (see section 6) <math>{{v}^{\ 2}}={{u}^{\ 2}}+2as</math> <math>\begin{align} & {{0}^{2}}={{50}^{2}}+2\tim...)
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Revision as of 14:39, 21 May 2010
We first obtain the acceleration \displaystyle a.
Using the kinematic equation (see section 6)
\displaystyle {{v}^{\ 2}}={{u}^{\ 2}}+2as
\displaystyle \begin{align} & {{0}^{2}}={{50}^{2}}+2\times a\times 300 \\ & \\ & a=-\frac{2500}{600}=-4.167\ \text{m}{{\text{s}}^{-2}} \\ \end{align}
