Solution 10.1b
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(New page: Image:10.1b.gif Here <math>T</math> is the tension in the cable and <math>a</math> is the acceleration of the packet. Applying Newton's second law <math>\begin{align} & \uparrow :\ ...)
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Revision as of 10:03, 20 May 2010
Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.
Applying Newton's second law
\displaystyle \begin{align} & \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9 \textrm{.}81= mg = 300\times 0 \textrm{.}1 \\ & \\ & T=30+2943\approx 2970\ \text{N} \\ \end{align}
