Solution 9.5
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(New page: Image:9.5.gif In the figure <math>R1</math> is the air resistance. Resolving up the plane <math>\begin{align} & F1+F-mg\sin {{30}^{\circ }}=0 \\ & \\ & F1=mg-F\sin {{30}^{\circ ...)
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Revision as of 12:09, 18 May 2010
In the figure \displaystyle R1 is the air resistance.
Resolving up the plane
\displaystyle \begin{align}
& F1+F-mg\sin {{30}^{\circ }}=0 \\
& \\
& F1=mg-F\sin {{30}^{\circ }}=60\times 9.81-\frac{1}{2}F \\
\end{align}
