Solution 8.10c
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(New page: We use the result from part a). <math>\mathbf{r}=(8\ \mathbf{i}+8 \ \mathbf{ j})t+\frac{1}{2}(0\textrm{.}01\mathbf{i}+0\textrm{.}02\mathbf{j}+0\textrm{.}1\mathbf{k}){{t}^{\ 2}}+10\mathbf{...)
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Revision as of 12:25, 20 April 2010
We use the result from part a).
\displaystyle \mathbf{r}=(8\ \mathbf{i}+8 \ \mathbf{ j})t+\frac{1}{2}(0\textrm{.}01\mathbf{i}+0\textrm{.}02\mathbf{j}+0\textrm{.}1\mathbf{k}){{t}^{\ 2}}+10\mathbf{k}\ , for any time \displaystyle t.
At the end when \displaystyle t=40 also from part a), we get
\displaystyle \mathbf{r}=(8\ \mathbf{i}+8 \ \mathbf{ j}) \times 40+\frac{1}{2}(0\textrm{.}01\mathbf{i}+0\textrm{.}02\mathbf{j}+0\textrm{.}1\mathbf{k}) \times{{40}^{\ 2}}+10\mathbf{k}=328\mathbf{i}+336\mathbf{j}+10\mathbf{k} \ , for any time \displaystyle t.
