Solution 8.9b
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(New page: We use <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> with <math>\mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math> <math>\mathbf{a}=-10\mathbf{j}</math> <math...)
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Revision as of 15:26, 19 April 2010
We use \displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t with
\displaystyle \mathbf{u}=15\mathbf{i}+18\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}
\displaystyle \mathbf{a}=-10\mathbf{j}
\displaystyle t=3\text{ s}
giving \displaystyle \mathbf{v}=15\mathbf{i}+18\mathbf{j}+(-10\mathbf{j} )\times 3
Simplifying \displaystyle \mathbf{v}=15\mathbf{i}+18\mathbf{j}-30\mathbf{j}=15\mathbf{i}-12\mathbf{j}
