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	Substituting these into the equation		Substituting these into the equation
	<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t \ \</math>		<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t \ \</math>
-	gives the velocity of the ball at time <math>t=10 \text{ s }</math> as:	+	gives the velocity of the particle at time <math>t=10 \text{ s }</math> as:
	<math>\mathbf{v}=4\mathbf{i}+(0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j})\times 10</math>		<math>\mathbf{v}=4\mathbf{i}+(0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j})\times 10</math>

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Revision as of 15:26, 13 April 2010

In this case we have \displaystyle \mathbf{u}=4\mathbf{i} and \displaystyle \mathbf{a}=0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j}

Substituting these into the equation \displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t \ \ gives the velocity of the particle at time \displaystyle t=10 \text{ s } as:

\displaystyle \mathbf{v}=4\mathbf{i}+(0\textrm{.}9\mathbf{i}+0\textrm{.}7\mathbf{j})\times 10

which gives

\displaystyle \mathbf{v}=13\mathbf{i}+9\mathbf{j} \ \text{ m}{{\text{s}}^{\text{-1}}}