Solution 6.10a
From Mechanics
(Difference between revisions)
(New page: Using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}</math> gives <math>s=0+\frac{1}{2}\times 2\times {{4}^{2}}=16\ \text{m}</math>) |
(New page: Using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}</math> gives <math>s=0+\frac{1}{2}\times 2\times {{4}^{2}}=16\ \text{m}</math>) |
Current revision
Using \displaystyle s=ut+\frac{1}{2}a{{t}^{\ 2}} gives
\displaystyle s=0+\frac{1}{2}\times 2\times {{4}^{2}}=16\ \text{m}
