Solution 6.6b

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(New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 24-9=0\textrm{.}5t \\ & t=30\ \text{s} \\ \end{align}</math> Here we have used the result for the acceleration obtained in the...)
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(New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 24-9=0\textrm{.}5t \\ & t=30\ \text{s} \\ \end{align}</math> Here we have used the result for the acceleration obtained in the...)
 

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Using \displaystyle v=u+at\ \ gives

\displaystyle \begin{align} & 24-9=0\textrm{.}5t \\ & t=30\ \text{s} \\ \end{align}

Here we have used the result for the acceleration obtained in the first part.