Solution 6.4b
From Mechanics
(Difference between revisions)
(New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 15=5+0\textrm{.}2\times t \\ & \\ \end{align}</math> where we have used the acceleration calculated in part a). This gives <...) |
(New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 15=5+0\textrm{.}2\times t \\ & \\ \end{align}</math> where we have used the acceleration calculated in part a). This gives <...) |
Current revision
Using \displaystyle v=u+at\ \ gives
\displaystyle \begin{align} & 15=5+0\textrm{.}2\times t \\ & \\ \end{align}
where we have used the acceleration calculated in part a).
This gives
\displaystyle t=50\ \text{s}