Solution 5.7a
From Mechanics
(Difference between revisions)
(New page: Resolving to the right, <math>45\ \text{N}-T\cos {{60}^{\circ }}=0</math> giving <math>T=\frac{45}{0\textrm{.}5}=90\ \text{N}</math>) |
(New page: Resolving to the right, <math>45\ \text{N}-T\cos {{60}^{\circ }}=0</math> giving <math>T=\frac{45}{0\textrm{.}5}=90\ \text{N}</math>) |
Current revision
Resolving to the right,
\displaystyle 45\ \text{N}-T\cos {{60}^{\circ }}=0
giving
\displaystyle T=\frac{45}{0\textrm{.}5}=90\ \text{N}
