Solution 5.5c
From Mechanics
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(New page: Image:5.5.gif The horisontal component <math>H</math> of the 5000 N force is <math>H=5000\cos {{25}^{\circ }}=4531\ \text{N}</math> The maximum friction is <math>\mu R=0.3\times...) |
(New page: Image:5.5.gif The horisontal component <math>H</math> of the 5000 N force is <math>H=5000\cos {{25}^{\circ }}=4531\ \text{N}</math> The maximum friction is <math>\mu R=0.3\times...) |
Current revision
The horisontal component \displaystyle H of the 5000 N force is
\displaystyle H=5000\cos {{25}^{\circ }}=4531\ \text{N}
The maximum friction is \displaystyle \mu R=0.3\times 2787=836\ \text{N}
This is less then \displaystyle H. Thus the maximum friction \displaystyle 836\ \text{N} will come into play.
