Solution 4.8b
From Mechanics
(Difference between revisions)
(New page: Image:4.8b.gif <math>\tan \alpha =\frac{12}{9}=1\textrm{.}33</math> giving <math>\alpha =53\textrm{.}1{}^\circ</math>) |
(New page: Image:4.8b.gif <math>\tan \alpha =\frac{12}{9}=1\textrm{.}33</math> giving <math>\alpha =53\textrm{.}1{}^\circ</math>) |
Current revision
\displaystyle \tan \alpha =\frac{12}{9}=1\textrm{.}33
giving
\displaystyle \alpha =53\textrm{.}1{}^\circ
