Solution 4.8a

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(New page: <math>{\mathbf{F}_{1}}</math> = (<math>9\mathbf{i}+12\mathbf{j}</math>) N <math>\sqrt{{{9}^{2}}+{{12}^{2}}}=15\ \text{N}</math>)
Current revision (15:43, 24 March 2010) (edit) (undo)
(New page: <math>{\mathbf{F}_{1}}</math> = (<math>9\mathbf{i}+12\mathbf{j}</math>) N <math>\sqrt{{{9}^{2}}+{{12}^{2}}}=15\ \text{N}</math>)
 

Current revision

\displaystyle {\mathbf{F}_{1}} = (\displaystyle 9\mathbf{i}+12\mathbf{j}) N

\displaystyle \sqrt{{{9}^{2}}+{{12}^{2}}}=15\ \text{N}