Solution 4.1

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(New page: Using <math>\begin{align} & \mathbf{F}=F\cos \alpha \mathbf{i}+F\sin \alpha \mathbf{j} \end{align}</math> where <math>\alpha</math> is <math>30{}^\circ</math> and <math>F=80\ \text{N...)
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(New page: Using <math>\begin{align} & \mathbf{F}=F\cos \alpha \mathbf{i}+F\sin \alpha \mathbf{j} \end{align}</math> where <math>\alpha</math> is <math>30{}^\circ</math> and <math>F=80\ \text{N...)
 

Current revision

Using

\displaystyle \begin{align} & \mathbf{F}=F\cos \alpha \mathbf{i}+F\sin \alpha \mathbf{j} \end{align}

where \displaystyle \alpha is \displaystyle 30{}^\circ and \displaystyle F=80\ \text{N} gives

\displaystyle \mathbf{F}=69.3 \displaystyle \mathbf{i} \displaystyle + 40 \displaystyle \mathbf{j} \text { N}