Solution 3.9a
From Mechanics
(Difference between revisions)
| Line 4: | Line 4: | ||
<math>\begin{align} | <math>\begin{align} | ||
& \uparrow \ R-mg=0 \\ | & \uparrow \ R-mg=0 \\ | ||
| - | & R=200\times 9.8=1960\ \text{N} \\ | + | & R=200\times 9\textrm{.}8=1960\ \text{N} \\ |
\end{align}</math> | \end{align}</math> | ||
Revision as of 16:30, 3 February 2011
\displaystyle \begin{align}
& \uparrow \ R-mg=0 \\
& R=200\times 9\textrm{.}8=1960\ \text{N} \\
\end{align}
