Answer 16.2
From Mechanics
(Difference between revisions)
(New page: 60 <math>\text{m}{{\text{s}}^{-1}}</math>) |
(New page: 60 <math>\text{m}{{\text{s}}^{-1}}</math>) |
Current revision
60 \displaystyle \text{m}{{\text{s}}^{-1}}
