Answer 8.6a
From Mechanics
(Difference between revisions)
(New page: <math>\left( \frac{1}{2}\mathbf{i}-\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-2}}}</math>) |
(New page: <math>\left( \frac{1}{2}\mathbf{i}-\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-2}}}</math>) |
Current revision
\displaystyle \left( \frac{1}{2}\mathbf{i}-\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-2}}}
