Answer 8.2

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(New page: a) <math>\left( 5\mathbf{i}-16\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-1}}}</math> b) <math>\left( 58\mathbf{i}-114\mathbf{j} \right)\text{ m}</math>)
Current revision (15:47, 12 September 2009) (edit) (undo)
(New page: a) <math>\left( 5\mathbf{i}-16\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-1}}}</math> b) <math>\left( 58\mathbf{i}-114\mathbf{j} \right)\text{ m}</math>)
 

Current revision

a) \displaystyle \left( 5\mathbf{i}-16\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-1}}}

b) \displaystyle \left( 58\mathbf{i}-114\mathbf{j} \right)\text{ m}