Introduction to forces
From Mechanics
(New page: ==Newton's First Law== A particle will move with a constant velocity or remain at rest if the resultant force on the particle is zero. '''Equilibrium''' If the resultant force on a par...) |
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<math>\text{5}.\text{98}\times \text{1}0^{\text{24}}\text{ }</math> | <math>\text{5}.\text{98}\times \text{1}0^{\text{24}}\text{ }</math> | ||
kg | kg | ||
+ | |||
+ | |||
+ | '''[[Example 2.1]]''' | ||
+ | |||
+ | Describe whether or not the forces acting on the following objects are in equilibrium: | ||
+ | |||
+ | (a) A passenger in a train that travels at a constant speed. | ||
+ | |||
+ | (b) A hot air balloon rising at a constant rate. | ||
+ | |||
+ | (c) A stone dropped into a very deep well full of water. | ||
+ | |||
+ | '''Solution''' | ||
+ | |||
+ | (a) Yes, if it is travelling in a straight line. | ||
+ | |||
+ | (b) Yes, if it is travelling in a straight line. | ||
+ | |||
+ | (c) Yes, if it reaches a terminal velocity, so that it is travelling in a straight line at a constant speed. | ||
+ | |||
+ | |||
+ | '''[[Example 2.2]]''' | ||
+ | |||
+ | Find the magnitude of the force of gravity (weight) acting on a lorry of mass 22 tonnes. | ||
+ | |||
+ | '''Solution''' | ||
+ | |||
+ | This is calculated using the fact that the weight is given by mg. | ||
+ | |||
+ | |||
+ | <math>\begin{align} | ||
+ | & mg=22000\times 9.8 \\ | ||
+ | & =215600\text{ N} | ||
+ | \end{align}</math> | ||
+ | |||
+ | |||
+ | The diagram shows the lorry and its weight. | ||
+ | |||
+ | |||
+ | |||
+ | Note that reaction forces also act upwards on each wheel. | ||
+ | |||
+ | |||
+ | <math>R_{1}+R_{2}+R_{3}+R_{4}=215600</math> |
Revision as of 14:59, 13 March 2009
Newton's First Law
A particle will move with a constant velocity or remain at rest if the resultant force on the particle is zero.
Equilibrium
If the resultant force on a particle is zero, then the forces acting on the particle are said to be in equilibrium.
The Universal Law of Gravitation
\displaystyle F=\frac{Gm_{1}m_{2}}{d^{2}}
\displaystyle G=6.67\times 10^{-11}\text{ kg}^{\text{-1}}\text{m}^{\text{3}}\text{s}^{\text{-2}}
Gravity on Earth
The force of gravity is often called the weight.
\displaystyle \begin{align}
& F=mg \\
& g=9.8\text{ ms}^{\text{-2}} \\
\end{align}
Data
Radius of Earth is
\displaystyle \text{6}.\text{37}\times \text{1}0^{\text{6}}\text{ }
metres
Mass of Earth is \displaystyle \text{5}.\text{98}\times \text{1}0^{\text{24}}\text{ } kg
Describe whether or not the forces acting on the following objects are in equilibrium:
(a) A passenger in a train that travels at a constant speed.
(b) A hot air balloon rising at a constant rate.
(c) A stone dropped into a very deep well full of water.
Solution
(a) Yes, if it is travelling in a straight line.
(b) Yes, if it is travelling in a straight line.
(c) Yes, if it reaches a terminal velocity, so that it is travelling in a straight line at a constant speed.
Find the magnitude of the force of gravity (weight) acting on a lorry of mass 22 tonnes.
Solution
This is calculated using the fact that the weight is given by mg.
\displaystyle \begin{align}
& mg=22000\times 9.8 \\
& =215600\text{ N}
\end{align}
The diagram shows the lorry and its weight.
Note that reaction forces also act upwards on each wheel.
\displaystyle R_{1}+R_{2}+R_{3}+R_{4}=215600