Solution to Test Paper 1

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& \mu =\frac{3 \textrm{.}6}{19 \textrm{.}6}=0 \textrm{.}184 \\
& \mu =\frac{3 \textrm{.}6}{19 \textrm{.}6}=0 \textrm{.}184 \\
\end{align}</math>
\end{align}</math>
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& R+T\sin 30{}^\circ =200\times 9 \textrm{.}8 \\
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& R+0 \textrm{.}5T=1960 \\
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& R=1960-0 \textrm{.}5T \\
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\end{align}</math>
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<math>\begin{align}
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& F=T\cos 30{}^\circ \\
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& T\cos 30{}^\circ =0\textrm{.}6(1960-0\textrm{.}5T) \\
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& T(\cos 30{}^\circ +0\textrm{.}3)=1176 \\
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& T=\frac{1176}{(\cos 30{}^\circ +0\textrm{.}3)}=1010\text{ N} \\
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\end{align}</math>
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Revision as of 17:33, 18 January 2011

Solutions
1 (a) \displaystyle \begin{align}

& {{0}^{2}}={{7}^{2}}+2(-\textrm{.}8)s \\ & s=\frac{49}{19\textrm{.}6}=2\textrm{.}5 \\ & \text{Max Height }=\text{ 5}+\text{2}\text{.5}=\text{7}\text{.5 m} \\ \end{align}

(3 marks)


1 (b) \displaystyle \begin{align}

& 0=7-9\textrm{.}8t \\ & t=\frac{7}{9\textrm{.}8}=0\textrm{.}714\text{ s} \\ \end{align}

(3 marks)
(6 marks)


2 (a) \displaystyle \begin{align}

& T-800\times 9\textrm{.}8=800\times 0\textrm{.}2 \\ & T=\text{7840}+\text{160}=\text{8000 N} \\ \end{align}

(3 marks)


2 (b) \displaystyle \begin{align}

& T-800\times 9\textrm{.}8=800\times (-0\textrm{.}2) \\ & T=\text{7840}-\text{160}=\text{7680 N} \\ \end{align}

(3 marks)


2 (c) \displaystyle T=800\times 9\textrm{.}8=7840\text{ N} (1 mark)


(7 marks)


3 (a) Image:test1ans1.gif (1 mark)


3 (b) \displaystyle F=2\times 1\textrm{.}8=3\textrm{.}6\text{ N} (2 marks)


3 (c) \displaystyle R=2\times 9\textrm{.}8=19\textrm{.}6\text{ N} (2 marks)


3 (d) \displaystyle \begin{align}

& 3 \textrm{.}6=19 \textrm{.}6\mu \\ & \mu =\frac{3 \textrm{.}6}{19 \textrm{.}6}=0 \textrm{.}184 \\ \end{align}

(3 marks)


(8 marks)


4 (a) Image:test1ans2.gif (1 mark)


4 (b) \displaystyle \begin{align}

& R+T\sin 30{}^\circ =200\times 9 \textrm{.}8 \\ & R+0 \textrm{.}5T=1960 \\ & R=1960-0 \textrm{.}5T \\ \end{align}

(3 marks)


4 (c) \displaystyle

\displaystyle \begin{align} & F=T\cos 30{}^\circ \\ & T\cos 30{}^\circ =0\textrm{.}6(1960-0\textrm{.}5T) \\ & T(\cos 30{}^\circ +0\textrm{.}3)=1176 \\ & T=\frac{1176}{(\cos 30{}^\circ +0\textrm{.}3)}=1010\text{ N} \\ \end{align}

(4 marks)


(8 marks)


5 (a) go here more cells in the same row here even more cells in the same row here


5 (b) more cells in the same row here even more cells in the same row here


5 (c) more cells in the same row here even more cells in the same row here


5 (d) more cells in the same row here even more cells in the same row here


cells in the next row go here more cells in the same row here even more cells in the same row here


cells in the next row go here more cells in the same row here even more cells in the same row here


Row heading 1 Cell 2 Cell 3
Row heading A Cell B Cell C
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