Solution 20.5a
From Mechanics
(Difference between revisions)
(New page: <math>F=m\frac{{{v}^{2}}}{r}=1500\times \frac{{{15}^{2}}}{80}=4129\text{ N}</math>) |
(New page: <math>F=m\frac{{{v}^{2}}}{r}=1500\times \frac{{{15}^{2}}}{80}=4129\text{ N}</math>) |
Current revision
\displaystyle F=m\frac{{{v}^{2}}}{r}=1500\times \frac{{{15}^{2}}}{80}=4129\text{ N}
