Answer 19.8b

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(New page: <math>\left( 40t \right)\mathbf{i}+\left( -2t+400 \right)\mathbf{j}</math>)
Current revision (17:51, 27 March 2011) (edit) (undo)
 
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<math>\left( 40t \right)\mathbf{i}+\left( -2t+400 \right)\mathbf{j}</math>
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<math>\left( 40t \right)\mathbf{i}+\left( {-{t}^{2}}+400 \right)\mathbf{j}</math>

Current revision

\displaystyle \left( 40t \right)\mathbf{i}+\left( {-{t}^{2}}+400 \right)\mathbf{j}