Answer 19.8a

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(New page: <math>\left( 40 \right)\mathbf{i}+\left( -2t \right)\mathbf{j}</math>)
Current revision (16:45, 11 October 2010) (edit) (undo)
(New page: <math>\left( 40 \right)\mathbf{i}+\left( -2t \right)\mathbf{j}</math>)
 

Current revision

\displaystyle \left( 40 \right)\mathbf{i}+\left( -2t \right)\mathbf{j}