Processing Math: Done
Solution 19.6b
From Mechanics
(Difference between revisions)
(New page: <math>\begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...) |
(New page: <math>\begin{align} & s=\int_{0}^{10}{\left( 3{{t}^{2}}+2t+5 \right)}dt \\ & \\ & =\left[ {{t}^{3}}+{{t}^{2}}+5t \right]_{0}^{10} \\ & \\ & =\left( {{10}^{3}}+{{10}^{2}}+5\times 10 \...) |
Current revision
010
3t2+2t+5
dt=
t3+t2+5t
010=103+102+5
10−0=1150 m
