Answer 19.3b
From Mechanics
(Difference between revisions)
m (New page: <math>40\text{ m}{{\text{s}}^{\text{-1}}}</math>) |
m (New page: <math>40\text{ m}{{\text{s}}^{\text{-1}}}</math>) |
Current revision
\displaystyle 40\text{ m}{{\text{s}}^{\text{-1}}}
