Processing Math: Done
Solution 19.2b
From Mechanics
(Difference between revisions)
(New page: <math>\begin{align} & s(50)=\int_{0}^{50}{v}dt \\ & \\ & =\int_{0}^{50}{\left( \frac{{{t}^{2}}}{50}+2 \right)dt} \\ & \\ & =\left[ \frac{{{t}^{3}}}{150}+2t \right]_{0}^{50} \\ & \\...) |
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| + | Using the result for the velocity obtained in part a) | ||
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<math>\begin{align} | <math>\begin{align} | ||
& s(50)=\int_{0}^{50}{v}dt \\ | & s(50)=\int_{0}^{50}{v}dt \\ | ||
Current revision
Using the result for the velocity obtained in part a)
050vdt=050
t250+2
dt=
t3150+2t
050=503150+2
50−0=933 m
