Solution 19.1a
From Mechanics
(Difference between revisions)
(New page: <math>\begin{align} & v=\int{a}dt=t-\frac{{{t}^{2}}}{30}+c \\ & t=0,\ \ v=0\Rightarrow c=0 \\ & v=t-\frac{{{t}^{2}}}{30} \\ \end{align}</math>) |
(New page: <math>\begin{align} & v=\int{a}dt=t-\frac{{{t}^{2}}}{30}+c \\ & t=0,\ \ v=0\Rightarrow c=0 \\ & v=t-\frac{{{t}^{2}}}{30} \\ \end{align}</math>) |
Current revision
\displaystyle \begin{align} & v=\int{a}dt=t-\frac{{{t}^{2}}}{30}+c \\ & t=0,\ \ v=0\Rightarrow c=0 \\ & v=t-\frac{{{t}^{2}}}{30} \\ \end{align}
