Solution 18.8d
From Mechanics
(Difference between revisions)
(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=-\frac{1}{5}\mathbf{i}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector pointing in the opposite direction to <math>\mathbf{i}</math>, ...) |
(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=-\frac{1}{5}\mathbf{i}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector pointing in the opposite direction to <math>\mathbf{i}</math>, ...) |
Current revision
\displaystyle \mathbf{a}=\frac{d\mathbf{v}}{dt}=-\frac{1}{5}\mathbf{i}\ \text{m}{{\text{s}}^{-2}}
This is a constant vector pointing in the opposite direction to \displaystyle \mathbf{i}, that is to the west.
