Solution 18.8a

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(New page: <math>\begin{align} & 2t-\frac{{{t}^{2}}}{10}=0 \\ & t\left( 2-\frac{t}{10} \right)=0 \\ & t=0\text{ or }t=20 \\ \end{align}</math> <math>t=0</math> is not of physical interest thus th...)
Current revision (18:39, 8 October 2010) (edit) (undo)
(New page: <math>\begin{align} & 2t-\frac{{{t}^{2}}}{10}=0 \\ & t\left( 2-\frac{t}{10} \right)=0 \\ & t=0\text{ or }t=20 \\ \end{align}</math> <math>t=0</math> is not of physical interest thus th...)
 

Current revision

\displaystyle \begin{align} & 2t-\frac{{{t}^{2}}}{10}=0 \\ & t\left( 2-\frac{t}{10} \right)=0 \\ & t=0\text{ or }t=20 \\ \end{align}

\displaystyle t=0 is not of physical interest thus the answer is \displaystyle t=20\ \text{s}.