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Solution 18.7c

From Mechanics

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(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=6\mathbf{j}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector with magnitude <math>6\ \text{m}{{\text{s}}^{-2}}</math> and points vertica...)
Current revision (18:31, 8 October 2010) (edit) (undo)
(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=6\mathbf{j}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector with magnitude <math>6\ \text{m}{{\text{s}}^{-2}}</math> and points vertica...)
 

Current revision

a=dtdv=6j ms−2

This is a constant vector with magnitude 6 ms−2 and points vertically upwards (j direction).

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