Solution 18.7c
From Mechanics
(Difference between revisions)
(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=6\mathbf{j}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector with magnitude <math>6\ \text{m}{{\text{s}}^{-2}}</math> and points vertica...) |
(New page: <math>\mathbf{a}=\frac{d\mathbf{v}}{dt}=6\mathbf{j}\ \text{m}{{\text{s}}^{-2}}</math> This is a constant vector with magnitude <math>6\ \text{m}{{\text{s}}^{-2}}</math> and points vertica...) |
Current revision
\displaystyle \mathbf{a}=\frac{d\mathbf{v}}{dt}=6\mathbf{j}\ \text{m}{{\text{s}}^{-2}}
This is a constant vector with magnitude \displaystyle 6\ \text{m}{{\text{s}}^{-2}} and points vertically upwards (\displaystyle \mathbf{j} direction).
