Answer 18.7b
From Mechanics
(Difference between revisions)
(New page: <math>\text{89}\textrm{.}\text{4 m}{{\text{s}}^{-\text{1}}}</math>) |
(New page: <math>\text{89}\textrm{.}\text{4 m}{{\text{s}}^{-\text{1}}}</math>) |
Current revision
\displaystyle \text{89}\textrm{.}\text{4 m}{{\text{s}}^{-\text{1}}}
