Solution 18.2a
From Mechanics
(Difference between revisions)
(New page: <math>\begin{align} & v=\frac{ds}{dt}=10t-6 \\ & a=\frac{dv}{dt}=10\ \text{m}{{\text{s}}^{-2}} \\ \end{align}</math>) |
(New page: <math>\begin{align} & v=\frac{ds}{dt}=10t-6 \\ & a=\frac{dv}{dt}=10\ \text{m}{{\text{s}}^{-2}} \\ \end{align}</math>) |
Current revision
\displaystyle \begin{align} & v=\frac{ds}{dt}=10t-6 \\ & a=\frac{dv}{dt}=10\ \text{m}{{\text{s}}^{-2}} \\ \end{align}
